
Assuming equipid is required, the following result was found.
the following expression as the one we use to get the equipment information: SELECT DISTINCT re.[RoomId] ,re.[SiteId] ,re.[EquipId] ,eq.[Description] FROM [ROOMEQUIPMENT] re INNER JOIN [EQUIPMENT] eq ON eq.EquipId=re.EquipId WHERE re.RoomId=@GivenRoom...

bc1qf6elrdxc968h0k673l2djc9wrpazhqtxw8qqp4
0xb038962F3809b425D661EF5D22294Cf45E02FebF